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WASSCE SHS

WASSCE Chemistry: The mole

The mole is the amount of substance that contains 6.02 × 10²³ particles. Mass divided by molar mass gives the amount.

The idea

Molar mass is the mass of one mole, in grams. For carbon dioxide, carbon is 12 and each oxygen is 16, so the molar mass is 44 g. Amount in moles is mass divided by molar mass. 11 g of carbon dioxide is 11/44, which is 0.25 mol. The number of molecules is that amount times 6.02 × 10²³. Keep the unit. A bare 0.25 is not an amount of substance until you say mol.

An empirical formula is the simplest whole number ratio of atoms. Convert a mass of each element to moles by dividing by the relative atomic mass, then divide every result by the smallest number of moles. If a result is not a whole number, multiply all of them by the same small integer until they are. A molecular formula is a multiple of the empirical formula. You need the relative molecular mass to find that multiple. Without it, stop at the empirical formula and say so.

What earns the marks

Show mass divided by molar mass. The arithmetic mark is separate from the method mark. Relative atomic masses will be given or are the familiar whole numbers: C = 12, H = 1, O = 16. Do not invent a molar mass. For an empirical formula, the order of elements in the answer should follow the question. CH₂ is not H₂C in the way most schemes print it, though a reversed order of the same ratio is usually accepted if you have said what you are doing.

Practice questions

These are practice questions in the style of the paper, with a model answer and a mark scheme. They are not a promise of what your paper will ask.

1Question 1

2 marks

Calculate the amount, in moles, in 11 g of carbon dioxide. Relative atomic masses: C = 12, O = 16. (2 marks)

Model answer

Molar mass = 12 + 16 + 16 = 44 g. Amount = 11/44 = 0.25 mol.

Mark scheme

  • Molar mass 44 g, or 44 g mol⁻¹1 mark
  • 0.25 mol1 mark

2Question 2

3 marks

A compound contains 0.24 g of carbon and 0.04 g of hydrogen only. Find the empirical formula. C = 12, H = 1. (3 marks)

Model answer

Moles of C = 0.24/12 = 0.02. Moles of H = 0.04/1 = 0.04. Ratio = 0.02 : 0.04 = 1 : 2. Empirical formula CH₂.

Mark scheme

  • Moles of carbon 0.02 and moles of hydrogen 0.041 mark
  • Ratio 1 to 21 mark
  • CH₂1 mark

3Question 3

2 marks

The relative molecular mass of the compound in the previous question is 28. Find the molecular formula. (2 marks)

Model answer

The empirical formula mass of CH₂ is 14. 28/14 = 2. Molecular formula C₂H₄.

Mark scheme

  • Multiple is 28/14 = 21 mark
  • C₂H₄1 mark

Practise Chemistry with Anna

More questions on this topic are inside GLearn, marked as you answer, with the reason written out. The first ones need no account.

Practise Chemistry free

All WASSCE Chemistry past questions

Other topics in this subject

  • Atomic structure
  • Chemical bonding
  • Acids, bases and salts
  • Organic chemistry
  • All WASSCE Chemistry past questions

Questions about The mole

How do you find the amount in moles from a mass?+

Divide the mass in grams by the molar mass. For carbon dioxide the molar mass is 44 g, so 11 g is 0.25 mol. Multiply by 6.02 × 10²³ if the question asks for the number of molecules.

What is an empirical formula?+

The simplest whole number ratio of atoms in a compound. Find the moles of each element, divide by the smallest, and write the formula. The molecular formula may be a whole number multiple of that ratio. You need the relative molecular mass to decide. All WASSCE Chemistry past questions

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